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al noor:
Hello,
I attached a file ,,, could some1 please help me by writting the answers as i want to check them..
Thankyou in advance :D

cooldude:

--- Quote from: al noor on November 13, 2009, 06:27:23 pm ---Hello,
I attached a file ,,, could some1 please help me by writting the answers as i want to check them..
Thankyou in advance :D

--- End quote ---

since nobodys told u until now, so i thought i wud and i also saw some easy qs :D , sorry but i cant answer all of them since im still doing igcse maths. neway ur answers--

a) i) V=15000-(2000*3)
=>£9000
ii)10000=15000-2000t
t=(10000-15000)/-2000
t=7 yrs
iii) this is because after 4 yrs the gradient does not remain constant and after 4 yrs the gradient does not remain -2000

b) i) 5000=18275e-0.24t
=>5000/18275=e-0.24t
=>t=5.4004 yrs

ii) % error=(error/actual value)*100
error=1700-[18275*e-0.24*10]
error=£42.1294
=> % error=(42.1294/1700)*100
=> % error=2.4782%

c) i) i don't know
ii) £/yr
iii) the gradient represents the rate of decrease of the value of the car over time
d) i don't know

hope i helped

astarmathsandphysics:
d)Not ksqrt(t) because the value increases from the graph. The other one is better V=18275*e-0.24*t

al noor:
Thankyouuu :P

--- Quote from: cooldude on November 13, 2009, 09:13:05 pm ---since nobodys told u until now, so i thought i wud and i also saw some easy qs :D , sorry but i cant answer all of them since im still doing igcse maths. neway ur answers--

a) i) V=15000-(2000*3)
=>£9000
ii)10000=15000-2000t
t=(10000-15000)/-2000
t=7 yrs
iii) this is because after 4 yrs the gradient does not remain constant and after 4 yrs the gradient does not remain -2000

b) i) 5000=18275e-0.24t
=>5000/18275=e-0.24t
=>t=5.4004 yrs

ii) % error=(error/actual value)*100
error=1700-[18275*e-0.24*10]
error=£42.1294
=> % error=(42.1294/1700)*100
=> % error=2.4782%

c) i) i don't know
ii) £/yr
iii) the gradient represents the rate of decrease of the value of the car over time
d) i don't know

hope i helped



--- End quote ---

al noor:
Thankyoouu soo much :D

--- Quote from: astarmathsandphysics on November 13, 2009, 09:28:13 pm ---d)Not ksqrt(t) because the value increases from the graph. The other one is better V=18275*e-0.24*t

--- End quote ---

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