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Author Topic: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)  (Read 4041 times)

Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #30 on: November 10, 2009, 04:54:00 pm »
sorry i was away,
trying it now
this method is little different and making it little confusing
trying now

is there any such rule that sec x tan x should be > 0 or something
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #31 on: November 10, 2009, 05:11:45 pm »
ok got that part

confusion confusion confusion
in that site....

when they find the derivative of sec inverse for the range (pi/2) till pi.
they get a negative sign in the denomintor before the square root
how is that now
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Offline Tyserius

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time
« Reply #32 on: November 10, 2009, 05:39:00 pm »
Quote from: sgvaibhav on November 10, 2009, 05:11:45 pm
ok got that part

confusion confusion confusion
in that site....

when they find the derivative of sec inverse for the range (pi/2) till pi.
they get a negative sign in the denomintor before the square root
how is that now

'Cause for cos x where pi/2 < x < pi, it is negative haha.
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #33 on: November 10, 2009, 06:12:38 pm »
this was truly confusing  >:( :(
it will be very hard to explain.

but why do we need to care to put modulus
if there is no modulus, then the answer comes negatives (LET IT STAY NEGATIVE IF IT IS NEGATIVE  >:()

annoying  :-\
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #34 on: November 10, 2009, 06:18:58 pm »
yep one more thing
when sec goes negative, tan also goes negative
so negative x negative = positive

im going off pc now probably
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Offline astarmathsandphysics

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time
« Reply #35 on: November 10, 2009, 06:21:24 pm »
I differenthated them all but i posted in the ib board
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #36 on: November 10, 2009, 06:25:22 pm »
nice
lol i edited the main page
haha
warning

thanks for help :D

will never forget this now.
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Offline Tyserius

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time
« Reply #37 on: November 10, 2009, 06:35:51 pm »
Quote from: sgvaibhav on November 10, 2009, 06:18:58 pm
yep one more thing
when sec goes negative, tan also goes negative
so negative x negative = positive

im going off pc now probably

Yep yep! Haha that explains the modulus :) Anyway, all the best for the presentation xD
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #38 on: November 10, 2009, 06:49:32 pm »
loooooooool
haha, that -ve x -ve = +ve was a doubt
but when u said it explains the modulus, i realised that the doubt is the solution ???
cya tom
thanks for help
bye
Take care
goodnight
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Offline Tyserius

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time
« Reply #39 on: November 10, 2009, 07:18:10 pm »
Quote from: sgvaibhav on November 10, 2009, 06:49:32 pm
loooooooool
haha, that -ve x -ve = +ve was a doubt
but when u said it explains the modulus, i realised that the doubt is the solution ???
cya tom
thanks for help
bye
Take care
goodnight

Haha! Take care and goodnight :)
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Offline astarmathsandphysics

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #40 on: November 10, 2009, 10:21:22 pm »
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #41 on: November 11, 2009, 09:20:47 am »
 :(

sir wanted it written in a paper, while i thought it had to be explained to the full class.
now i will open word 2007, write down steps, print it and give it to him
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Offline Tyserius

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time
« Reply #42 on: November 11, 2009, 09:25:29 am »
Quote from: sgvaibhav on November 11, 2009, 09:20:47 am
:(

sir wanted it written in a paper, while i thought it had to be explained to the full class.
now i will open word 2007, write down steps, print it and give it to him

Lol. But did you get everything now? :) I guess you've done it all :D
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Offline SGVaibhav

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Re: help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
« Reply #43 on: November 11, 2009, 01:37:50 pm »
yeah i got it
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