Author Topic: Math Heeelppp!!  (Read 3018 times)

Offline Tyserius

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Re: Math Heeelppp!!
« Reply #15 on: November 08, 2009, 06:06:04 pm »
Here you go! The other document will be posted once I'm done :)

EDIT : 7.docx is completed!
« Last Edit: November 08, 2009, 06:22:58 pm by Tyserius »
Take it easy and go slow and steady.

Offline Tyserius

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Re: Math Heeelppp!!
« Reply #16 on: November 08, 2009, 06:23:32 pm »
I hope this doesn't show spam but.. al noor! I'm done! Refer to previous reply :)
Take it easy and go slow and steady.

Offline al noor

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Re: Math Heeelppp!!
« Reply #17 on: November 08, 2009, 07:24:24 pm »
Here you go! The other document will be posted once I'm done :)

EDIT : 7.docx is completed!

Thankyouuu soo mucchhh ;)

Offline Tyserius

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Re: Math Heeelppp!!
« Reply #18 on: November 08, 2009, 08:10:06 pm »
No prob :) hope it helps!
Take it easy and go slow and steady.

Offline al noor

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Re: Math Heeelppp!!
« Reply #19 on: November 08, 2009, 09:56:55 pm »
No prob :) hope it helps!

It helped me soo mucch.:D:D:D:D
Thankyou and thankyou astar

Offline xxemoxx

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Re: Math Heeelppp!!
« Reply #20 on: November 13, 2009, 12:49:02 pm »
I have a question
Show that the curves y=2x^2 + 5x , y= x^2 + 4x + 12, y=3x^2 + 4x - 6 have one point in common and find its coordinate   its from the book P1 Mathematics ( AS LEVEL CAMBRIDGE)
 thanks
i need an urgent solution pleasee..
cheers:D

Offline astarmathsandphysics

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Re: Math Heeelppp!!
« Reply #21 on: November 13, 2009, 12:59:23 pm »
1)y=2x^2 + 5x
2)7=x^2 + 4x + 12
3)y=3x^2 + 4x - 6
1)=2) 2x^2 + 5x =x^2 + 4x - 12
x^2+x-12=0=(x+4)(x-3) so x=-4,3
1)=3)2x^2 + 5x =3x^2 + 4x - 6
so x^2-x-6= 0 so (x+2)(x-3)=0 so x=-2,3
2)=3)x^2 + 4x +12=3x^2+4x-6 so2x^2-18=0 so x^2=9 so x=3, -3
ans is x=3
y=x^2+4x+12=9+12+12=33

Offline xxemoxx

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Re: Math Heeelppp!!
« Reply #22 on: November 13, 2009, 01:40:11 pm »
hey, thanks alot it really helped.

Offline xxemoxx

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Re: Math Heeelppp!!
« Reply #23 on: November 13, 2009, 01:55:28 pm »
I have another question
The line y = 6x + 1 meets the curve y=x^2 + 2x + 3 at two points. Answers are in surds..
source: Q22 P1 AS LEVEL maths cie

Offline astarmathsandphysics

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Re: Math Heeelppp!!
« Reply #24 on: November 13, 2009, 02:02:03 pm »
6x + 1=x^2 + 2x + 3
x^2-4x+2=0
x=(-b+_sqrt(b^2-4ac))/2a=(4+-sqrt(16-8))/2=2+-sqrt(2)