okay guys...another one...
A mercury thread of a thermometer is 12mm long when placed in melting ice, and 82mm long when placed in boiling water.
Find the:
a)length of the thread at 50oC
b)temperature when the length is 61mm long
plss guys, i need a full-fledged explanation for this cuz whenever i see this type of question after say 2-3 days, i tend to again do it wrong....plsss tell me a way to remember it forever....
Thanks guys!!
look adi we knw that b/w 12mm and 82mm lies 100
.c. cuz melting point of ice=0 and boiling point of water=100. therefore in this scale 1mm=(82-12)/100
=>7/10=0.7
=>1
.c=0.7mm
therfore at 50
.c length=12+(0.7*50)=47mm
and then the next part=>
1
.c=0.7mm
therefore the length for which there is a temperature change=>61-12=49mm
therfore the temperature at this=>49/0.7=70
.c
just do it by simple unitary method
got it?