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Author Topic: vectors- As physics  (Read 1668 times)

Offline Sue T

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vectors- As physics
« on: December 13, 2009, 01:45:22 pm »
does any1 have any notes for vectors? cuz they're really tricky! :o
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nid404

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Re: vectors- As physics
« Reply #1 on: December 13, 2009, 01:53:51 pm »
Vectors for AS physics are really easy....just work on sums in ur text and past papers...if u don't get any post them here, and we'll do it for u

I will look for notes on vectors anyway...try S-cool Physics...maybe that'll help
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nid404

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Re: vectors- As physics
« Reply #2 on: December 13, 2009, 01:55:26 pm »
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nid404

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Re: vectors- As physics
« Reply #3 on: December 13, 2009, 01:56:45 pm »
oh & if u want me to give u questions to do...I'll be glad to help and c how much you could do by yourself....lemme knw  :)
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Offline girl_92

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Re: vectors- As physics
« Reply #4 on: December 13, 2009, 06:00:25 pm »
nid can u solve this 4 me i have an exam tommorow i wuld be relli thnkful
a student standin on a railway platform notices tth the first two carriages of an arriving train passes her in 2 sec and the nxt two in 2.4 s
the train is decelaratin uniformly.each carriage is 20m long when the train stops the student is opposite the last carriae how many carriages are there in the train
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some people sleep to dream while othrs wakeup to follow dem im the second type how abt u

Offline astarmathsandphysics

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Re: vectors- As physics
« Reply #5 on: December 14, 2009, 08:30:58 am »
When i get up
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Offline astarmathsandphysics

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Re: vectors- As physics
« Reply #6 on: December 14, 2009, 10:28:49 am »
Use s=ut+1/2at^2 twice

For the first two carriages
40=2u+2a
For the first for carraiges
80=4.4u+9.68a
Solve thes to get u=710/33
a=-50/33
then train takes s=(v^2-u^2)/2a=(710/33)^2/(2*50/33)=148.9
8 carrariages
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Offline Sue T

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Re: vectors- As physics
« Reply #7 on: December 14, 2009, 02:12:21 pm »
thank you so much
 i'll study from the website u gave then if u can upload the questions it'll be great cuz i do need some practice :D
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Offline girl_92

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Re: vectors- As physics
« Reply #8 on: December 15, 2009, 07:46:34 am »
Quote from: astarmathsandphysics on December 14, 2009, 10:28:49 am
Use s=ut+1/2at^2 twice

For the first two carriages
40=2u+2a
For the first for carraiges
80=4.4u+9.68a
Solve thes to get u=710/33
a=-50/33
then train takes s=(v^2-u^2)/2a=(710/33)^2/(2*50/33)=148.9
8 carrariages
Thanks  alot sir
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some people sleep to dream while othrs wakeup to follow dem im the second type how abt u
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