Qualification > Math
math paper 4 help...!!!
@d!_†oX!©:
--- Quote from: wassup on November 03, 2009, 11:10:43 am ---this is d conversion of d new doc only to pdf.
plz check this n tell me that r there all d things that uve written????
--- End quote ---
everything is there but y is it goin all out???
leave it naa man...use the docx file dt i hav posted!!!
wassup:
--- Quote from: @d!_†oX!© on November 03, 2009, 11:16:35 am ---everything is there but y is it goin all out???
leave it naa man...use the docx file dt i hav posted!!!
--- End quote ---
ive converted that file only n i dnt have office 07...so thanks just wanted 2 confirm that all d things r there.
@d!_†oX!©:
see things are there...but its cuz that 2003 file is kinda weird so the things got out of shape...so u acnt view them properly....otherwise evrything is there....i think the docx shud also openin 2003 cuz i maintained the compatibility wid 2003 too
wassup:
--- Quote from: @d!_†oX!© on November 03, 2009, 11:20:39 am ---see things are there...but its cuz that 2003 file is kinda weird so the things got out of shape...so u acnt view them properly....otherwise evrything is there....i think the docx shud also openin 2003 cuz i maintained the compatibility wid 2003 too
--- End quote ---
ok it's f9...n thanks again.
Ghost Of Highbury:
just a suggestion for all matrix transformation Qs
instead of remembering all base vectors ,..do this
suppose its a stretch with x-axis invariant and stretch factor 2
so..
always transform 2 points
1st --> 1,0
2nd --> 0,1
1,0 to 1,0 (strect of scale factor 2 but x-axis invariant)
0,1 to 0,2 ( ll )
put that as a matrix
(1 0)
(0 2) (put only the cordinates of the image, in vertical form)
this can be done for all transformations
we do it this way, its easier than remembering all..
for complicated ones use
(a b) * (ox1 ox2) = (ix1 ix2)
(c d) (oy1 oy2) (iy1 iy2)
ox/y = object cordinates
ix/y = image cordinated
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