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Maths P4 doubt

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eightAs:
ABE ~ GFE ~ CDE
Let the area of ABE be k
GFE will also be k since the question says both are congruent.
Look at the area of CDE
Ar.(CDE):Ar.(GFE) = (2/1)^2 = 4
hence ar(CDE)=4k
Shaded area = 4k-k = 3k
Total area = CDE+ABE = 5k
%age = 60%/

yathubhai:
thankz loaddzzz eightAs!!
i understud it!! :D :)

@d!_†oX!©:

--- Quote from: M.@.N.B.i.R. on November 02, 2009, 10:10:44 am ---i think its 0.5 x diagonal 1 x diagonal 2

--- End quote ---
ya ur right!!

@d!_†oX!©:
hey yathubhai!!!
check this out...these are the model answers to the same question...
shud be helpful!!!
http://www.freeexampapers.us/IGCSE/Maths/CIE/2003%20Jun/IGCSE%20Maths%20Paper%204%20model%20answers.pdf

@d!_†oX!©:
hey did u say both parts???
i just read it on ur first post...
so here u go!!
Diagram 5 :-
shaded area = (pi r220)/360
whole area = (pi r2180)/360
thus shaded area/whole area gives 20/180 => 1/9

Diagram 6 :-
shaded area = pi 12
whole area = pi 52
thus, shaded area/whole area gives 12/52 => 1/25

Diagram 7 :-
shaded area = [(pi 32theta)/360] - [(pi 22theta)/360]
shaded area => (5 pi theta)/360
whole area = (pi 32theta)/360
thus, shaded area/whole area gives 5/9


 :) :) :)

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