FRICTION !!!!!!!! HELP!!!!

[astarmathsandphysics]

for the 1st
>2T root 3  /2-Troot 3 /2=ma  so Troot 3 /2=ma m=maa osf ball
res vertically 2T/2+T=mg so T=2mg/3
then from first eq a=2mg/3 *root 3 /2m=groot 3 /3 =

[astarmathsandphysics]

working back for the secon one I get the acceleration of the bead is 7g/4 which is impossible

[astarmathsandphysics]

I can see the problem now. As the bead is moving down the string., the string is accelerating upwards so the length of time will be shorter. I have to find the acceleration of the m particle

[astarmathsandphysics]

I think I have it. Solve the equations a1+a2=g
and a2=g/4 to get a1=3g/4 then string is passing through bead at 2a1+a2=7g/4 and use s=1/2at^2 with a =7g/4

[nid404]

THank YoU Very MucH Sir

[nid404]

Need help again

Find the acceleration of the wedge shown in the figure if the mass of the wedge is 4 times the mass of the block. All surfaces are frictionless. The angle of the inclined surface of the wedge is 37^o with the horizontal.

[astarmathsandphysics]

It will be late tonight when i answer this.

[nid404]

It will be late tonight when i answer this.

np

[nid404]

Well I'd have to add a few more to this I'm dumb u c


In the figure shown,pulley and strings are light and inextensible.Initially all the bodies are at rest when string connecting A and B is cut. Find the initial acceleration of A,C and the pulley

[nid404]

Anybody give it try plzz.....

[123]

hey nid about that wedge n block.....heres what i did wit my m1 knowledge n a lil thinkin 


Since all surfaces r frictionless, the wedge resting on ground would slip as the block moves down. So i guess v need to split the component of block's weight (4mg) into a force pushing the wedge... so that it slips left
I don't think this is the right way...mayb astar can help
Interestin ques...even i wanna know the answer 

did u ask in goiit.com?

[nid404]

Thanks for givin it a try

I saw that site. I registered but I'm still to ask questions there....thanks a lot tho

[astarmathsandphysics]

For the pulley when the string is cut there is a resultant for ce mg due to the tension in the spring acting on a total mass of 3m hence using F=ma
mg=3ma so a =g/3
(The tension initially is 4mg becasue`the system is in equilibrium)

resolving vertically for A
T-mg=ma
and for B
2mg-T=2ma
solve these to get a=g/3
so the acceleration of A is g/3+g/3=2g/3 and the acceleration of B is g/3-g/3=0

[astarmathsandphysics]

For the black and wedge problem try this attachement

[nid404]

thanks sir...