Qualification > Sciences
igcse physics ppr 6 DOUBT
holychalice:
ok
1. a - Avg = (26.8 + 26.8 + 27 + 26.9 + 27 + 27) / 6 = 26.9 OC
- 0.1 OC
The largest temperature difference is very low ... Less than even 5% or even 1% of d avg temperature .. so we can take it as constant
b - 0 cm3 as the volume remained 14 aall d tym
3.1 x 2 = 6.2 cm3 This is because d volumes given are h/cm but we have a 2cm3 of tube so double.
13.9 x 2 = 27.8 cm3
Avg u can do it = 27.8/5 = 5.6 cm3
I guess this is d way ...
moon:
Avg = (26.8 + 26.8 + 27 + 26.9 + 27 + 27) / 6 = 26.9 OC
why did u divide it by 6???
Avg u can do it = 27.8/5 = 5.6 cm3
and here why did u divide it by 5???
holychalice:
c d table noe :
dere six values for room temperature :
for avg temperature .. u hav 6 observations ..
at 0hr , 1hr, 2hr, 3hr, 4hr and 5hr ...
nd divided by 5 ... cuz we r checking d rate of water lost in 5 hrs ... dats d experiment ... so its kept for 5 hrs ... ... so for 5 hrs .. 27.8 divided by 5 ...nd u hav 5 hrs of observation for d water loss so divided by 5
got it ?
read this again ... ive modified it
moon:
Why don't we take the initial time ??? ???
Ghost Of Highbury:
--- Quote from: moon on November 02, 2009, 10:13:41 am ---Why don't we take the initial time ??? ???
--- End quote ---
ok..its simple ratio
27.8cm3 of water lost in 5 hours
how much lost in 1 hour?
5 hours - 27.8
1 hours - 27.8/5 *1 = 5.56cm3/h
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version