Qualification > Math
Add. math!! dude slvri/astar/aadi/sam nebody help..!!!!!
vaan:
aadi how u put dat "ROOT OVER"
~~~~shreyapril~~~~:
--- Quote from: vaan on November 12, 2009, 04:16:52 pm ---i know its a complicated way of showin....but im new so not dat much experienced....
u found perfect square in (i)...
use dat 1 2 find de g-1
(i) =2(X-2)2+1....
let g(x)= y
y=2(x-2)2 +1...
(y-1)/2= (x-2)2...
{(y-1)/2}1/2= (x-2)...
[{(y-1)/2}1/2]+2=x...
hence g-1(x)=[{(x-1)/2}1/2]+2...
NOW PUT K VALUE....K=2...
g-1(2)=9/4
--- End quote ---
i guess it must be -3
Ghost Of Highbury:
its latex
click on the pi symbol
and type in sqrt(watever u want to type)
like this
@shrey - what guess!, it has to be -3 @vaan - dude, good method, but check ur complete the square thingy its not +1 its -3
@d!_†oX!©:
...
Ghost Of Highbury:
yes
there are many more things with latex
u can use integration, fraction symbols and stuff
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