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Author Topic: IGCSE Maths doubt(paper 4)  (Read 12696 times)

nid404

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Re: IGCSE Maths doubt(paper 4)
« Reply #30 on: October 31, 2009, 03:13:54 pm »
summin like that....can't you
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #31 on: October 31, 2009, 03:15:59 pm »
Quote from: nid404 on October 31, 2009, 03:13:54 pm
summin like that....can't you
arre..show na how u used it..is it the same formula?
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nid404

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Re: IGCSE Maths doubt(paper 4)
« Reply #32 on: October 31, 2009, 03:18:21 pm »
Quote from: A@di on October 31, 2009, 03:15:59 pm
arre..show na how u used it..is it the same formula?

yaa..
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #33 on: October 31, 2009, 03:23:34 pm »
Quote from: nid404 on October 31, 2009, 03:18:21 pm
yaa..
kk..i have used that to calculate the length
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #34 on: November 01, 2009, 10:55:36 am »
hmm
aadi is there some simple method to get the answer for that question???

i did not understand ne thing!!!
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #35 on: November 01, 2009, 11:04:46 am »
Quote from: ~~~~shreycool~~~~ on November 01, 2009, 10:55:36 am
hmm
aadi is there some simple method to get the answer for that question???

i did not understand ne thing!!!
check the formula for the magnitude of a vector
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #36 on: November 01, 2009, 11:06:26 am »
kk
By the way i wanted for the 16 wala ans
not for the length!!!
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #37 on: November 01, 2009, 11:19:11 am »
what u didnt understand exactly?

now dont say everything..
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #38 on: November 01, 2009, 11:20:55 am »
no
got it!!
u explained it on phone!!
done i guess will solve it agian
in same meadtod then i'll undertand
By the way you staying after school irte??
tmr?? for 2 min!!
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #39 on: November 01, 2009, 11:22:31 am »
Quote from: ~~~~shreycool~~~~ on November 01, 2009, 11:20:55 am
no
got it!!
u explained it on phone!!
done i guess will solve it agian
in same meadtod then i'll undertand
By the way you staying after school irte??
tmr?? for 2 min!!
u guyz have a horrible habit of deviating away from the topic...
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Offline @d!_†oX!©

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Re: IGCSE Maths doubt(paper 4)
« Reply #40 on: November 01, 2009, 11:23:38 am »
its not merely a habit bro....its our moto
haha
EADA's moto
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #41 on: November 01, 2009, 11:24:09 am »
haha
thanx
By the way om me or ans my question here only!!
if you dont mind!!

By the way wait a sec there is one more question to come check my thread abt ad. math!!
i'll post it there!!
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Alpha

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Re: IGCSE Maths doubt(paper 4)
« Reply #42 on: November 01, 2009, 02:27:52 pm »
Quote from: A@di on October 31, 2009, 03:10:29 pm
@nid - show how did u use the distance formula?

-----
BC = k-6)i + 15j

sqrt((k-6)^2 + 15^2) = 25

therefore

(k-6)2 = 252 - 152 = 400

k-6= sqrt(400) = 20

hence, k = 26


I answered the second part only... He or she just asked for second part...lol

That's the first part! Distance formula is used in 2nd part...
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Alpha

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Re: IGCSE Maths doubt(paper 4)
« Reply #43 on: November 01, 2009, 02:38:28 pm »
Hey... The Distance Formula is derived from the Pythagoras' Theorem... That's not difficult to understand.

Use the graphical method...

Draw any inclined line on a Cartesian Plane.

I have attached a file to this post. Refer to it.

Let A (x, y) and B(x1, y1).

To find the distance between A and B, i.e, the bold black inclined line, you will need to find the length of the two red dotted lines I have named x and y.

Using Pythagoras' Theorem,

Square of longest side = Sum of squares of the two smallest sides.

Send square to the other side...

>>> Longest side=  Sq. root of the sum.

And to find the two smallest sides:

        x = 3 - 0 [y1 - y]

        y = 3 - 0 [x1 - x]

Note that the triangle formed is a right-angled one.

And now substituting the values for x and y, you will come back to the distance formula given.

Actually, this formula is just another way of using the Pythagoras' Theorem. A diagram would help. But it takes time to draw... Maybe by Tuesday, I'll post the diagram here... It would be easy to understand then.

This formula is used both in Maths and Add Maths.

Good Luck! 
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nid404

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Re: IGCSE Maths doubt(paper 4)
« Reply #44 on: November 01, 2009, 02:52:49 pm »
Gradient formula should be used for the second 1....but for the first one i think we need to used distance formula....they did something else.....

so aadi....could u use the distance formula FOR the first one ??

@alpha-i know he asked for the 2nd one ans I know the stuff.....I was asking abt the first part cuz I used the distance formula for the first one and got a different answer
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