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HELP IGCSE MATH JUN. 09 ppr 2

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moon:
Sorry still didn't get it. ??? ???Please help

@d!_†oX!©:
dude see
there are four angles in total....two opposite each other...
so when u have to draw the locus of points equidistant from both these lines...u gotta make the angle bisector for all four angles which is same as making two angle bisectors of the opposite angles

moon:
Sorry once again Why didn't we draw the perpendicular bisector as usual???? ???

Ghost Of Highbury:
perpendicular bisector can be drawn for a line.(1800)..for an angle..its angle bisector

nid404:

--- Quote from: moon on October 27, 2009, 02:44:07 pm ---Sorry still didn't get it. ??? ???Please help

--- End quote ---

Do you know how to draw an angle bisector??

I'll put the steps down for u

Let the point of intersection of the two line be called M

First draw angle bisector for AM and BM. keep your compass and M and take a radius more than half of AM/BM and cut the two lines  and call them points X and Y. With the same radius draw an arc from X and cut the arc with same radius from Y. Join M with the intersection of the arcs. Repeat for other lines.

I'll post another diagram below

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