Author Topic: igcse physics ppr 6 DOUBT  (Read 3262 times)

Offline moon

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Re: igcse physics ppr 6 DOUBT
« Reply #15 on: November 02, 2009, 09:17:54 am »
please can u help in Jun.1999 ppr 6 Q.3 (a) & (b ii) ???

Offline holychalice

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Re: igcse physics ppr 6 DOUBT
« Reply #16 on: November 02, 2009, 09:20:35 am »
can u put up d paper ?? or d question ??
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nid404

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Re: igcse physics ppr 6 DOUBT
« Reply #17 on: November 02, 2009, 09:21:46 am »
please can u help in Jun.1999 ppr 6 Q.3 (a) & (b ii) ???

yes please...i don'y have da paper

Offline moon

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Re: igcse physics ppr 6 DOUBT
« Reply #18 on: November 02, 2009, 09:33:38 am »
ok, I will try.

Offline moon

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Re: igcse physics ppr 6 DOUBT
« Reply #19 on: November 02, 2009, 09:40:02 am »
here is the question ???

Offline holychalice

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Re: igcse physics ppr 6 DOUBT
« Reply #20 on: November 02, 2009, 09:49:57 am »
ok
1. a - Avg = (26.8 + 26.8 + 27 + 26.9 + 27 + 27) / 6 = 26.9 OC
      - 0.1 OC
         The largest temperature difference is very low ... Less than even 5% or even 1% of d avg temperature .. so we can take it as constant
    b - 0 cm3   as the volume remained 14 aall d tym
         3.1 x 2 = 6.2 cm3                                 This is because d volumes given are h/cm    but we have a 2cm3 of tube so double.
         13.9 x 2 = 27.8 cm3 
     Avg u can do it = 27.8/5 = 5.6 cm3

I guess this is d way ...
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Offline moon

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Re: igcse physics ppr 6 DOUBT
« Reply #21 on: November 02, 2009, 10:02:11 am »
Avg = (26.8 + 26.8 + 27 + 26.9 + 27 + 27) / 6 = 26.9 OC

why did u divide it by 6???

 Avg u can do it = 27.8/5 = 5.6 cm3

and here why did u divide it by 5???

Offline holychalice

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Re: igcse physics ppr 6 DOUBT
« Reply #22 on: November 02, 2009, 10:09:06 am »
c d table noe :
dere six values for room temperature :
for avg temperature .. u hav 6 observations ..
at 0hr , 1hr, 2hr, 3hr, 4hr and 5hr ...

nd divided by 5 ... cuz we r checking d rate of water lost in 5 hrs ... dats d experiment ... so its kept for 5 hrs ... ... so for 5 hrs .. 27.8 divided by 5 ...nd u hav 5 hrs of observation for d water loss so divided by 5

got it ?
read this again ... ive modified it
« Last Edit: November 02, 2009, 10:27:41 am by M.@.N.B.i.R. »
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Offline moon

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Re: igcse physics ppr 6 DOUBT
« Reply #23 on: November 02, 2009, 10:13:41 am »
Why don't we take the initial time ??? ???

Offline Ghost Of Highbury

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Re: igcse physics ppr 6 DOUBT
« Reply #24 on: November 02, 2009, 11:50:35 am »
Why don't we take the initial time ??? ???

ok..its simple ratio

27.8cm3 of water lost in 5 hours

how much lost in 1 hour?

5 hours - 27.8

1 hours - 27.8/5 *1 = 5.56cm3/h
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Offline moon

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Re: igcse physics ppr 6 DOUBT
« Reply #25 on: November 02, 2009, 12:02:05 pm »
I've got it. Thank u both 4 helping me. :)

Offline Ghost Of Highbury

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Re: igcse physics ppr 6 DOUBT
« Reply #26 on: November 02, 2009, 12:03:58 pm »
I've got it. Thank u both 4 helping me. :)
ur welcome..
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