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Math paper4 Jun. 2009 help

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Ghost Of Highbury:
n ono...its not that simple

its the u/v method

here

d/dx (u/v) = (vdu-udv)/v2
break the expressin into two halves

1. x/2

2. 2/x

first..

u = x
v = 2
du = 1
dv = 0

->(vdu-udv)/v2

= 2/4

second..

u = 2
v =x
du = 0
dv = 1

(vdu-udv)/v2

=> (0-2)x2 = -2/x2

so the final differentiation = 1/2 - (-2/x2) = 1/2 + 2/x2

@d!_†oX!©:

--- Quote from: A@di on November 03, 2009, 08:33:15 am ---its difficult to learn differentiation in such a short span of..there are different methods for different type

for e.g here...u have to apply the u/v rule..

so yea..maybe later..

--- End quote ---

ya ya...kk..
u teach me after the ig'z!!

lol:
OMG I'm such an idiot. This is exactly the kind of thing i'm going to do tomorrow. I can do the work but I just make so many errors. After substituting x=2 into the equation i forgot to multiply by 2 before adding a half.

Thank you all so much and sorry about the hassle

Ghost Of Highbury:

--- Quote from: lol on November 03, 2009, 08:52:13 am ---OMG I'm such an idiot. This is exactly the kind of thing i'm going to do tomorrow. I can do the work but I just make so many errors. After substituting x=2 into the equation i forgot to multiply by 2 before adding a half.

Thank you all so much and sorry about the hassle

--- End quote ---

thats k..

~~~~shreyapril~~~~:
baapre aadi yuo tuped so much just to explain him differentiation!!

i guess adi toxic is now scared!!

By the way there is one trick by differentiation you can find the equation of the normal and tangnt in maths !!

i ahve used it many times!!
although this is not correct method!!

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