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MATH AS QUESTIONS>>>

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Eamyzz:

--- Quote from: astarmathsandphysics on October 15, 2009, 09:53:40 am ---Get there early. Be at peace. Maybe read an exam paper but probably not answer any questions

--- End quote ---
thnk u mr. paul =)

Eamyzz:

--- Quote from: slvri on October 15, 2009, 10:35:35 am ---nope not me.......im giving AS and A2 math in june 2010

--- End quote ---

gd luck slvri  ;) ;)

Eamyzz:
hey all hw was da paper?? =)

sanity_master:
i got a question in M1

N 03.....#7 (IV)


i solved almost 3/4 of it....but the final part doesnt wanna get right....so would some1 plz solve IV

Ghost Of Highbury:

--- Quote from: sanity_master on October 18, 2009, 03:31:39 pm ---i got a question in M1

N 03.....#7 (IV)


i solved almost 3/4 of it....but the final part doesnt wanna get right....so would some1 plz solve IV

--- End quote ---
i can use my knowledge of physics and additional mathas to solve this.

first find the (t) where velocity of B is maximum
for this differentiate velocity and equate to 0

d/dx (0.06t - 0.00012t2) = 0.06 - 0.00024t

equate this to 0

0.06 - 0.00024t = 0
0.06 = 0.00024t
t = 0.06/0.00024 = 250s

now

at 250 seconds find the distance covered by B

for finding the distance integrate the velocity formula

<= integration symbol

<(0.06t - 0.00012t2) = 0.03t2 - 0.00004t3 + c

when t = 0 ; s =0 therefore c = 0

so apply t=250 in the formula

s = 0.03t2 - 0.00004t3

s = 1875 - 625 = 1250

-
now find the distance traveled by A

u gotta use the diagram for this.

first find the equation of the line AB for this .

u wud get the equation

y = 0.012x + 3.6

substitute x=250 here

y = 6.6

name this point C

find the area of the trapezium ACXY

u wud get the area(distance) as 855

now find the area of the triangle AXO = 240

thus, the total area (distance) = 240 + 855 = 1095

now 1250 - 1095 = 155m

hope that helped

find the diagram attached

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