Qualification > Sciences
Chemistry doubt....
			sameer210394:
			
			th question says....
the reaction shown occurs naturally.
        C6H12O6     ==>      6CO2  +  6H2O
         P                           Q            
which description of P and Q are correct?
        P is a Hydrocarbon               Q is an Acidic Oxide
A             Yes                                      Yes
B             Yes                                       no
C              no                                       Yes
D              no                                        no
I just ticked the option C and the answer was right but i donno how, so ca anybody plz explain be how do u  call Q an acidic oxide???
Thanks in advance...
		
			nid404:
			
			Well, hydrocarbons consist of only C and H atoms...so hence glucose is not hydrocarbon.....CO2 is acidic should be known :P....CO2 forms carbonic acid in soln...it's an acidic oxide...cummon dude
		
			Ghost Of Highbury:
			
			yeah..that was correct...
as nid said..CO2 forms carbonic acid
metal oxides forms an alkali when dissolved in water
and non-metal oxides form acid..
so..yaeh..C is a non-metal..so 
the answer is C
@nid - he has taken combined science dude...not pure chem/phy/bio
		
			nid404:
			
			oh ok....
		
			Ghost Of Highbury:
			
			
--- Quote from: sameer210394 on October 12, 2009, 04:23:49 pm ---th question says....
the reaction shown occurs naturally.
        C6H12O6     ==>      6CO2  +  6H2O
         P                           Q            
which description of P and Q are correct?
        P is a Hydrocarbon               Q is an Acidic Oxide
A             Yes                                      Yes
B             Yes                                       no
C              no                                       Yes
D              no                                        no
I just ticked the option C and the answer was right but i donno how, so ca anybody plz explain be how do u  call Q an acidic oxide???
Thanks in advance...
--- End quote ---
guess u 4got to add O2 in the reactants side... :P
		
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