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A2 vectors Question

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astarmathsandphysics:
Use cos x =u>v/|u||v|
Take u ast 2i-3j+6k and v as 1-2j+2k
This will give you the angle between the normal and sthe line. To find the angle plane and the line find 90-x

astarmathsandphysics:
For part 3 solve(r-A).(i-2j+2k)=0
i-2j+2k is the tangent vector of the line. any vector perpendiculr to this will give zero when we take the dot product.

loggerhead:
awesome thanks astar. i think i figured out another way for part three and that is find the cross product of the tangent vectors of l and the normal of p which finds a vector on p perpendicular to l.

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