Qualification > Math
Maths
Eamyzz:
hey all does any1 no da answer of May/june 2009 Q9 P1
Ghost Of Highbury:
no idea how to solve the ii part
heres the i) find dy/dx => let u=6 ; v= 3x-2
therefore => du/dx = 0 and dv/dx = 3
dy/dx = (vdu - udv)/v2 => (-18)/(3x-2)2
apply x =2 in dy/dx
u get
-18/16 = -1.125/
astarmathsandphysics:
30700/79.6-350=35.68 euros
sameer210394:
--- Quote from: ~Am~ on October 01, 2009, 07:23:32 pm ---refer to the diagram attached..
.
first find the area of CBD...pir2/4 = 3.14/4 = 0.785
now, the area in peach is = y; the green area = x
total area of square = 1
square comprises of 4 peach shaded region + 4 green shaded region + 1 z
= 4y + 4x + z =1 (1)
CBD = 0.785
therefore, the area of the remaining part = 1 - 0.785 = 0.215
this area comprises of 2 peach shaded region + 1 green shaded region = 2y + x = 0.215
rearrange => y=(0.215 - x)/2
put this value of 'y' in the (1) equation
7x + 2z = 1.785 (keep this equation in mind)
----------------------------------
now consider the sector CBD
area = 0.785
it comprises of 3 green + 2 peach + 1 z
3x + 2y + z = 0.785
substitute 'y' value here
y = (0.215 - x)/2
so that gives us...
2x + z = 0.57
--
now for the final sim. equations
7x + 2z = 1.785
2x + z = 0.57 (*2)
--------------------
7x + 2z = 1.785 (subtract them)
4x + 2z = 1.14
-----------------
3x = 0.645
x = 0.215
------------
substitute in any equation to find the value of z
lets use 2x + z = 0.57
(2*0.215) + z = 0.57
z = 0.57 - 0.43
z = 0.14
done!
--- End quote ---
Abbey Mallu, I solved the same question with sumit in our free period, lolz...
remember we had done these types of sums.
sameer210394:
--- Quote from: ~Am~ on October 01, 2009, 07:23:32 pm ---refer to the diagram attached..
.
first find the area of CBD...pir2/4 = 3.14/4 = 0.785
now, the area in peach is = y; the green area = x
total area of square = 1
square comprises of 4 peach shaded region + 4 green shaded region + 1 z
= 4y + 4x + z =1 (1)
CBD = 0.785
therefore, the area of the remaining part = 1 - 0.785 = 0.215
this area comprises of 2 peach shaded region + 1 green shaded region = 2y + x = 0.215
rearrange => y=(0.215 - x)/2
put this value of 'y' in the (1) equation
7x + 2z = 1.785 (keep this equation in mind)
----------------------------------
now consider the sector CBD
area = 0.785
it comprises of 3 green + 2 peach + 1 z
3x + 2y + z = 0.785
substitute 'y' value here
y = (0.215 - x)/2
so that gives us...
2x + z = 0.57
--
now for the final sim. equations
7x + 2z = 1.785
2x + z = 0.57 (*2)
--------------------
7x + 2z = 1.785 (subtract them)
4x + 2z = 1.14
-----------------
3x = 0.645
x = 0.215
------------
substitute in any equation to find the value of z
lets use 2x + z = 0.57
(2*0.215) + z = 0.57
z = 0.57 - 0.43
z = 0.14
done!
--- End quote ---
abbey yaar, Adi tera Answer wrong hai, the answer comes close to 0.31 . and think about this, because the area of the red outlined section was 0.57, and your answer(area of z, which is the largest portion of the red outlined part) is not even 1/3 of that area(0.57). I did this with my own method and got answer as 0.31 unit squared.
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