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gas laws..

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astarmathsandphysics:
For 10 min each, at 27 degrees celsius,from 2 identical holes,nitrogen and an unknown gas are leaked into a common vessel of 3 litre capacity. The resulting pressure is 4.18 bar and mixture contains 0.4 mole of nitrogen. WHat is the  molar mass of the unknown gas?
pv=nRT
4.18*10^5*0.003=n*8.31*300 so n=0.503 moles so 0.103 moles unknown gas. The kinetic energies are the same(=3/2kT=1/2mv^2) so v=k/sqrt(m) the unknown gas diffuses at 1/4 the rate of nitogen so its mass must be 16 times greater 16*15=240g/mol

nid404:
I didn't get it....do you mind explaining it please....

like why did u take V=0.003?? and the kinetic energy part of it

astarmathsandphysics:
3 litres =3000/1000000 m3
The kinetic energy of a gas molecule is 3/2kT so all the molecules have the same energy. The kinetic energy is given by 1/2mv^2 s0o mv^2 for nitrogen =mv^2 for the unknown gas so m is inversly proprtional to v^2. I will make a correction to my earlier post.

nid404:
thanks a lot astar :)

nid404:
It's me again ::)

A stopclock, connecting two bulbs of volumes 5l and 10l containing an ideal gas at 9atm and 6atm respectively is opened. What is the final pressure in the two bulbs??

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