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gas laws..

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astarmathsandphysics:
another question

0.23g of a volatile solute displaced 112ml of air at  NTP. Calculate the vapour density and the molecular weight of the substabce

density =0.23g/112cm^3 =2.3*10^-4 kg /112*10-6 m^3 =2.05 KG/m^3
 1 mol of a gas occupies 2240ml at ntp so we have 112/2240=0.5 mols.
0.5 mols weighs 0.23g so 1 mole weighs 0.23/0.05=46g
1 mol contains 6.023*10^23 molecules so 1 molecule weighs 0.046/6.023*10^23 kg

nid404:
answer is 46.02 and 23.01 ???

astarmathsandphysics:
46 and 23.

nid404:
isn't density supposed to be in the form g/cm^3......the mass of 1 mole is 46g...so is the density 46g/cm^3....can u just take it like that??

astarmathsandphysics:
g/cm3 would be 46/22400

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