another question
0.23g of a volatile solute displaced 112ml of air at NTP. Calculate the vapour density and the molecular weight of the substabce
density =0.23g/112cm^3 =2.3*10^-4 kg /112*10-6 m^3 =2.05 KG/m^3
1 mol of a gas occupies 2240ml at ntp so we have 112/2240=0.5 mols.
0.5 mols weighs 0.23g so 1 mole weighs 0.23/0.05=46g
1 mol contains 6.023*10^23 molecules so 1 molecule weighs 0.046/6.023*10^23 kg