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math doubts [NEW]

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Ghost Of Highbury:
first find where they intersect

x-1 = x2 - 5x -8

simplifies to

-x2 + 6x + 7 =0

x = -1                 x = 7
y = -2                 y= 6

------------------------------

y = -2x2 + qx + p

substitute the values

x = -1 ; u get p=q

substitute x=7 and 'q' for 'p' (because they are equal) ; u get q = 13

so the curve is

-2x2 + 13q + 13

@Z.J - equation of a circle?..or  area

zara:
yea aadi its equation of a circle as mentioned in my worksheet.:\

Ghost Of Highbury:

--- Quote from: Z.J. on October 31, 2009, 06:27:12 pm ---yea aadi its equation of a circle as mentioned in my worksheet.:\

--- End quote ---

ok..check this

http://www.analyzemath.com/CircleEq/CircleEq.html

so the answer wud be




By the way--did u understand the other question?

nid404:
she means equation addiii...

yeah It's

r=8cm....let centre be (h,k)
let point P be a point on the circumference of a circle with coordinates (x,y)

then

(x-h)2 + (y-k)2=r2

(x-h)2+(y-k)2=16(42)

I assume centre is (0,0) since it is not given

assuming....h and k become 0

x2+y2=16
equation is  x2+y2-16=0

nid404:
equation of the circle has the general form

x2+y2+2gx+2fy+c=0

where centre is (-g,-f) and radius is root of (g2+f2-c)

@adi...how do u use the square root sign??

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