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Math again urrrgghh
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IGCSE/GCSE/O & A Level/IB/University Student Forum
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Math again urrrgghh
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Topic: Math again urrrgghh (Read 3238 times)
nid404
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Re: Math again urrrgghh
«
Reply #15 on:
September 21, 2009, 04:46:45 am »
Quote from: eddie_adi619 on September 21, 2009, 04:44:00 am
i found this much easier thank k+1
but this is not linked correctly
why would you simply do it without a reason
as in
[1× 2 × 3 × 4 × 5 × . . . . . . . . (2n - 2) (2n - 1) (2n) ]/ n!
how does 2n!/n! become something like this....no...not getting it
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Ghost Of Highbury
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Re: Math again urrrgghh
«
Reply #16 on:
September 21, 2009, 04:49:50 am »
arre dude...
n! = 1 * 2 * 3 * 4 ......*n rite?
so (2n)! = 1*2*3*4.......2n..
suppose n = 3
n! = 1*2*3 = 6
2n = 6
6! = (2n)! = 1*2*3*4*5*6. = 720..
thats the rule///
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nid404
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Re: Math again urrrgghh
«
Reply #17 on:
September 21, 2009, 04:54:21 am »
I know that.....
but still note getting what is done there
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Math again urrrgghh
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