Qualification > Sciences
Moles Again...
Ghost Of Highbury:
--- Quote from: shreyapril on September 10, 2009, 02:16:59 pm ---I am sure abt his question as my teacher had given me this one it is not like the previous one..
Here it starts
>>>>>>>>>>>>>>>>
9.3g of impure Sodium bicarbonate[NaHCO3] was heated and 2.2g of CO2 was formed.
Calculate % purity of NAHCO3
pls hepl!!!
--- End quote ---
a simpler way of diong this is use ratio proportion
44g of CO2 is produced with - 84g of pure NAHCO3
therefore 2.24g of CO2 should be produced with - 84*2/44 * 2.24 = 8.55
8.55 / 9.2 * 100 = 93%
~~~~shreyapril~~~~:
oye it shud be 84*2
the equation for the same is..
2NaHCO3 --> Na2CO3 + CO2 + H2O
k..
so acc to u it will be
168/44*2.24=8.55
so purity wud be 8.55/9.3*100=91.96 [app]
Ghost Of Highbury:
--- Quote from: shreyapril on September 10, 2009, 03:27:09 pm ---oye it shud be 84*2
the equation for the same is..
2NaHCO3 --> Na2CO3 + CO2 + H2O
--- End quote ---
oh..missed that..
u shud have ritten the whole equation
astar missed it too..
u just rote CO2
yes its 84*2
Ghost Of Highbury:
--- Quote from: eddie_adi619 on September 10, 2009, 03:29:28 pm ---
--- Quote from: shreyapril on September 10, 2009, 03:27:09 pm ---oye it shud be 84*2
the equation for the same is..
2NaHCO3 --> Na2CO3 + CO2 + H2O
--- End quote ---
oh..missed that..
u shud have ritten the whole equation
astar missed it too..
u just rote CO2
yes its 84*2
--- End quote ---
i'm getting 92%
Ghost Of Highbury:
--- Quote from: shreyapril on September 10, 2009, 03:27:09 pm ---oye it shud be 84*2
the equation for the same is..
2NaHCO3 --> Na2CO3 + CO2 + H2O
k..
so acc to u it will be
168/44*2.24=8.55
so purity wud be 8.55/9.3*100=91.96 [app]
--- End quote ---
yes
thats wat i rote
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