3) In a tidal barrage scheme, the area of sea-water behind the barrage is 30km2, the tidal depth is 10m and the density of the sea-water is 1030 kg/m3
a) what is the energy possibly available from this scheme in one cycle of ebb and flow?
b) If one ebb and flow takes 12hrs and 40min, what avg power does this represent?
c) What practical problems are bound to occur if max energy output per cycle is to be achieved?
a)dE=ghdm=gh(30(1000)
2*1030dh) since the mass of water in layer dh, dm=pgAdh
Then E=
b)1.514*10^12/(12*3600+40*60)=33.21MW
c)Controlling the rate of flow to achieve steady output. It will be hard to maintain output near the endwhen pressure of water is low.