A(7,2) C(1,4) are two vertices of a square ABCD
(a)find the equation of the diagonol BD
(b) Find the coordinates of B and of D
a) gradient of AC=m=(4-2)/(1-7)=-1/3 Now use y-y1=m(x-x1)
y-2=-1/3(x-7) so y=-1/3x+13/3
AC=(-6,2) and BD is at right angles so BD=(2.6) so from centre to B=(1,3) and to D=(-1,-3). Ccentre is at midpoint of AC=1/2(7+1,2+4)=(4,3) so B=(1,3)+(4,3)=(5,6) and C=(-1,-3)+(4,3)=(3,0)