Author Topic: Help with vectors  (Read 1215 times)

Offline Priya

  • Newbie
  • *
  • Posts: 39
  • Reputation: 20
Help with vectors
« on: June 14, 2009, 10:23:38 am »


For the second part,
I've worked it out like this:
Cross product with Normal vector of plane 1 & 2
I got (6, -10, -7)
It's right as per the mark scheme...

But then, i'm not sure whether the following steps are good because the point on the line is not the same..

Let the point have an x-cordinate=0
2y-2z=2
-3y+6z=3

Solve simultaneously to get y=7 and z=5

The point of the line is (0,7,5)?

I'm trying this method the first time. Pls help me out, thanks
« Last Edit: June 14, 2009, 10:34:01 am by Priya »

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Help with vectors
« Reply #1 on: June 14, 2009, 10:56:58 am »
From the simultaneous equations i get z=2 and y=3

Offline Priya

  • Newbie
  • *
  • Posts: 39
  • Reputation: 20
Re: Help with vectors
« Reply #2 on: June 14, 2009, 11:01:35 am »
I've checked it again... got it now.

Thank you!!

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Help with vectors
« Reply #3 on: June 14, 2009, 11:13:22 am »
Put z= t say then x+2y-2t=2 and 2x-3y+6t=3

so x+2y+2t+2 (1)
and 2x-3y=-6t+3 (2)
2*(1)-(2) gives 7y=10t+1 so y=1/7+10/7t
3*(1)+2*(3) 7x=-6t+12 so x=12/7+6/7t

Then r(t)=(12/7,1/7,0)+(6/7,1/7,1)t

on my last post I was on a mobile phone and couldnt see the attachm,ent