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CHEMISTRY PAPER 1 HERE

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Ghost Of Highbury:
ohh..tks
but in the first one i explained pereviously

the sulphur gains oxygen atoms and its oxidation state also increases..
this proves that it is oxidation

but...in the second equation the sulphur's oxidation state doesn't change...

nid404:

--- Quote from: eddie_adi619 on June 11, 2009, 06:32:31 pm ---ohh..tks
but in the first one i explained pereviously

the sulphur gains oxygen atoms and its oxidation state also increases..
this proves that it is oxidation

but...in the second equation the sulphur's oxidation state doesn't change...

--- End quote ---

oxidation is also the gain of oxygen atoms, which sulphur has gained.

simba:
in question 38 june 08......

Bani:

--- Quote from: eddie_adi619 on June 11, 2009, 06:15:43 pm ---S has many oxidation states including -2,0,2,4,6...
in this particular reaction the oxidation state of S is "+2"
a decrease in oxidation state - reduction
an increase in oxidation state - oxidation

1.) S + O2 -> SO2
     here at the left handside, as sulphur exists itself (not compound), the oxidation state is 0
          at the right hand sidde it forms a compound and gains an oxidation state of +2 = this is oxidation
          whereas O has an oxidation state of "0" in the left hand side and decreases to -4 in the right hand side
               this is reduction

therefore its redox

--- End quote ---

Thanks a lot
+rep for you :D

nid404:

--- Quote from: simba on June 11, 2009, 06:47:38 pm ---in question 38 june 08......

--- End quote ---

it is petroleum

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