Qualification > Sciences
CHEMISTRY PAPER 1 HERE
Bani:
thanks a lot everyone!
someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?
sweetest angel:
--- Quote from: Bani on June 11, 2009, 05:47:16 pm ---thanks a lot everyone!
someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?
--- End quote ---
since in equation 3 no reactants have lost or gained electrons, oxygen or hydrogen!
Bani:
--- Quote from: sweetest angel on June 11, 2009, 05:51:43 pm ---
--- Quote from: Bani on June 11, 2009, 05:47:16 pm ---thanks a lot everyone!
someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?
--- End quote ---
since in equation 3 no reactants have lost or gained electrons, oxygen or hydrogen!
--- End quote ---
Ya,but why is equation 1 and 2 REDOX?
1 and 2 are only oxidation, not reduction...
please help...
sweetest angel:
--- Quote from: Bani on June 11, 2009, 06:00:38 pm ---
--- Quote from: sweetest angel on June 11, 2009, 05:51:43 pm ---
--- Quote from: Bani on June 11, 2009, 05:47:16 pm ---thanks a lot everyone!
someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?
--- End quote ---
since in equation 3 no reactants have lost or gained electrons, oxygen or hydrogen!
--- End quote ---
Ya,but why is equation 1 and 2 REDOX?
1 and 2 are only oxidation, not reduction...
please help...
--- End quote ---
i dnt quite get it but i guess since 1 and 2 r reversible reactions they r oxidised in forward and reduced in backward rit? :-\
Ghost Of Highbury:
S has many oxidation states including -2,0,2,4,6...
in this particular reaction the oxidation state of S is "+2"
a decrease in oxidation state - reduction
an increase in oxidation state - oxidation
1.) S + O2 -> SO2
here at the left handside, as sulphur exists itself (not compound), the oxidation state is 0
at the right hand sidde it forms a compound and gains an oxidation state of +2 = this is oxidation
whereas O has an oxidation state of "0" in the left hand side and decreases to -4 in the right hand side
this is reduction
therefore its redox
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