Author Topic: C1 & C2 Discussion here!  (Read 9166 times)

Offline omega007

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Re: C1 & C2 Discussion here!
« Reply #30 on: June 06, 2009, 06:07:01 pm »
The answers for the trigonometric identities (part a) were:

For tan x part: -45 and 135

For sin x part: 23.6 and 156.4

 ;D  ;D  ;D

Any other questions???

Offline onhsa

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Re: C1 & C2 Discussion here!
« Reply #31 on: June 06, 2009, 08:51:22 pm »
So, everyone, did you fall for THE TRICK?Well, we all know how "easy" 4sinx=3tanx was. But what of the hidden agenda Edexcel so kindly cooked up for us? The ones who think have gotten it "right" did this:

4sinx=3(sinx/cosx)
(4/3)(sinx)(cosx)=sinx
(4/3)(cosx)=1(sinx/sinx)
(4/3)(cosx)=1
cosx= 3/4
and they found values for x

however, we have missed out alot of the question... keep reading

correct:


4sinx=3(sinx/cosx)
4(sinxcosx)=3sinx
4(sinxcosx)-3sinx=0
sinx(4cosx-3)=0
sinx=0
& then find values for sinx=0 as well
cosx=3/4
find values of cosx

So we have missed a part of the question, please post what u've done here, cos  if no one's gotten it right fully, they may accept the incomplete version as a correct answer.


« Last Edit: June 06, 2009, 08:55:20 pm by onhsa »

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #32 on: June 06, 2009, 09:47:22 pm »
in c2 paper wat was anyone lograhtim question second part answer

master786

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Re: C1 & C2 Discussion here!
« Reply #33 on: June 06, 2009, 09:58:22 pm »
my friend got it the right way

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #34 on: June 06, 2009, 10:03:20 pm »
what was the answer anyone remember

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #35 on: June 06, 2009, 10:04:57 pm »
plzzz anyone tell

master786

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Re: C1 & C2 Discussion here!
« Reply #36 on: June 06, 2009, 10:05:23 pm »
8 and 1/8

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #37 on: June 06, 2009, 10:08:28 pm »
how answer can be 8 . can u tell me that log 2x + log 2x = 2log 2x can be possible.can u plzz write down all the steps
« Last Edit: June 06, 2009, 10:10:30 pm by motherheaven »

master786

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Re: C1 & C2 Discussion here!
« Reply #38 on: June 06, 2009, 10:10:25 pm »
it wud becum log2x  X log2x

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #39 on: June 06, 2009, 10:15:27 pm »
i m getting square root of 512

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #40 on: June 06, 2009, 10:17:40 pm »
ok in c2 paper in trapezium rule question what was the answer overestimate or underestimate.plzzzz reply
« Last Edit: June 06, 2009, 10:23:52 pm by motherheaven »

master786

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Re: C1 & C2 Discussion here!
« Reply #41 on: June 06, 2009, 10:24:47 pm »
overestimate

Offline motherheaven

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Re: C1 & C2 Discussion here!
« Reply #42 on: June 06, 2009, 10:28:04 pm »
thnxxx and in c1 paper there was one question of sketching graph in part b) we have drawn the graph what were we suppose to do in c) which was a very long equation.like (x-2)whole cube..................plzzz reply
« Last Edit: June 06, 2009, 10:34:27 pm by motherheaven »

Offline omega007

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Re: C1 & C2 Discussion here!
« Reply #43 on: June 07, 2009, 08:33:21 am »
Translate it in the x-direction +2 units.

Offline omega007

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Re: C1 & C2 Discussion here!
« Reply #44 on: June 07, 2009, 08:49:28 am »
@onhsa....how many marks may we lose for that?