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Pure math(p3)

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astarmathsandphysics:

--- Quote from: ITS MEE... on May 28, 2009, 02:43:25 pm ---can u integrate
sin^3xcosx
please :'(

--- End quote ---

orry i missed this earlier sub u=sinx then du=cosxdx so dx=1/cosxdu so you integrate

sin^3xcosxdx=sin^3xcosx(1/cosxdu)=u^3du and the ans =1/4u^4=1/4sin^4x

louis:
ITS MEE,

Attachment  (  complex  number )  for your attention.

twilight:

--- Quote from: astarmathsandphysics on May 28, 2009, 05:43:36 pm ---
--- Quote from: ITS MEE... on May 28, 2009, 02:43:25 pm ---can u integrate
sin^3xcosx
please :'(

--- End quote ---

orry i missed this earlier sub u=sinx then du=cosxdx so dx=1/cosxdu so you integrate

sin^3xcosxdx=sin^3xcosx(1/cosxdu)=u^3du and the ans =1/4u^4=1/4sin^4x

--- End quote ---

thksssss astar .. +rep

louis:
ITS mee,


Another attachment  (  vertices of triangle ).

LupeFiasco:
anybody here taking bio P4, please send me what's coming for the exam at genetick2004@hotmail.com . Thanks and god speed.

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