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Sweet_03:
Hello ,

I have a Question .. and I hope You Can Help Me

Paper 1 May-June 2005

Question 6 :
Given that the following functions is defined for the domain -2 ? x ? 3, Find The Range of

(i) f:x ? 2-3x
(ii) g:x ? |2-3x|
(iii) f:x ? 2-|3x|

Ok .. For the First one (i) i know it .. its -7 ? f(x) ? 8
But how does do i work it out for absolute values ?

astarmathsandphysics:

--- Quote from: Sweet_03 on June 02, 2009, 02:43:46 pm ---Hello ,

I have a Question .. and I hope You Can Help Me

Paper 1 May-June 2005

Question 6 :
Given that the following functions is defined for the domain -2 ? x ? 3, Find The Range of

(i) f:x ? 2-3x
(ii) g:x ? |2-3x|
(iii) f:x ? 2-|3x|

Ok .. For the First one (i) i know it .. its -7 ? f(x) ? 8
But how does do i work it out for absolute values ?

--- End quote ---
i)2-3*3,2-3*-2 ie  range is -7 to 8
ii)0 to 8 since|2-3x| cannot be -ve but is zero at x=2/3
ii)-7 to 2 sonve x<=2 and is -7 at x=3

sweetsh:
I didnt get the first part by the way 8)

astarmathsandphysics:

--- Quote from: Padapop on June 02, 2009, 02:17:08 pm ---Paper 2 May june 2004

Question 4

(1 + sec x) (cosec x - cot x) = tan x

Prove the identity. Shoot thats hard.

--- End quote ---

(1 + sec x) (cosec x - cot x)=(cosx + 1)/cosx* (1 - cosx)/sinx=(1-cos^2x)/(c0sxsinx)=sin^2x/cosxsinx=sinx/cosx=tanx

vanibharutham:
sweetsh, did u mean you didnt get what astar just explained?

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