Qualification > Math
Additional Math Help HERE ONLY...!
BlackBunny103:
Guys, I need help with this question.
Thanxx :D
J.Darren:
--- Quote from: jellybeans on June 10, 2010, 01:29:26 am ---:o heyyyyyy, i've got a doubt :(
to find when the curve crosses the x axis, we sub in y = 0 right?
so 6 sin(3x + pi/4) = 0
sin(3x + pi/4) = 0
(3x + pi/4) = sin-1 0
(3x + pi/4) = 0
3x = -pi/4
x = -1/12pi
but why does the MS say sin-1 0 = PI? isnt it supposed to be 0?? ??? help please! thanks in advanceeeee.
--- End quote ---
You are absolutely correct.
J.Darren:
--- Quote from: BlackBunny103 on June 10, 2010, 01:50:07 am ---Guys, I need help with this question.
Thanxx :D
--- End quote ---
Construct a right-angle triangle with the longest side pointing north-west (this is the compensate for the tide flow from west to east). The horizontal side with have a length of 2, whereas the vertical line with have a length of 1.5 (90/60), the longest side is the speed the boat travels when it is in still water. The angle would be the one between the vertical side and the longest side.
J.Darren:
--- Quote from: jellybeans on June 10, 2010, 01:29:26 am ---:o heyyyyyy, i've got a doubt :(
to find when the curve crosses the x axis, we sub in y = 0 right?
so 6 sin(3x + pi/4) = 0
sin(3x + pi/4) = 0
(3x + pi/4) = sin-1 0
(3x + pi/4) = 0
3x = -pi/4
x = -1/12pi
but why does the MS say sin-1 0 = PI? isnt it supposed to be 0?? ??? help please! thanks in advanceeeee.
--- End quote ---
Ah, I think I have figured out what has gone wrong, in this case you must use the second solution which is 360 degrees. When x = 0, 6 sin (45), for sure when y = 0, x cannot be smaller than 45 degrees :P
jellybeans:
*dum dum dummmmm* ;D
ADD MATH'S OVERRRRRRRR, WOOP
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