Qualification > Math
Additional Math Help HERE ONLY...!
xlane:
The value at angle pie/4 and at -pie/4 is equal from y =3 ..therefore equatn of axis of symmetry y=3..i.e C=3
period or range for 1 cycle is 180..use 180/b...so b=1
amplitude i.e height from axis of symmetry in either directn so 5-3=2, 3-1=2..therefore a=2
Alpha:
--- Quote from: BlackBunny103 on June 08, 2010, 12:48:16 am ---I need help with this question, how can you find a?
Thanxx :D
--- End quote ---
a is the amplitude.
You get it just by comparing to the y = tan x curve.
tan x passes through the origin, it's passing at 3. So there has been a translation of 3. Therefore, c =3.
tan pie/4 = 1. But on the graph it's 5. You take 5 - 3 to get the amplitude. (y = 3 is the axis of curve here)
a = 2
xlane:
The value at angle pie/4 and at -pie/4 is equal from y =3 ..therefore equatn of axis of symmetry y=3..i.e C=3
period or range for 1 cycle is 180..use 180/b...so b=1
amplitude i.e height from axis of symmetry in either directn so 5-3=2, 3-1=2..therefore a=2
Alpha:
--- Quote from: xlane on June 08, 2010, 01:26:00 am ---The value at angle pie/4 and at -pie/4 is equal from y =3 ..therefore equatn of axis of symmetry y=3..i.e C=3
period or range for 1 cycle is 180..use 180/b...so b=1
amplitude i.e height from axis of symmetry in either directn so 5-3=2, 3-1=2..therefore a=2
--- End quote ---
:) Just. :D
xlane:
Lol yeah..."just" tryna help....:D:D:D...tan curve usualy never comes..so i put in da explanation 2
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