Qualification > Math
Additional Math Help HERE ONLY...!
jellybeans:
--- Quote from: slvri on June 07, 2010, 03:39:25 pm ---thats because theyve given you the range for x but the angle whos sine is being taken in the question is x/2-1, not x so whatever angle you find after taking inverse sine will be for x/2-1, not x itself. thats why you have to convert the given range for x to a range for x/2-1
that means for the limits given (0 and 6pi) you divide by 2 to get x/2 and then subtract 1 to get x/2-1 which is the required range
and by the way i gave add math in june 2009 and i gave a level math in june 2010
so yeah just felt like helping others out for the add math exam tomorrow :)
oh and HI ASTAR....remember me?
--- End quote ---
:o OH, so every range they give you, you have to sub it in the ... thing like (x/2-1) to get the MAX value? does this apply to EVERY equation? thanks again :) :)
J.Darren:
--- Quote from: jellybeans on June 07, 2010, 02:11:31 pm ---Helloooo, :D
ummm i need help with Q2 please? :) i can find the first two values but... how do you find the rest? :o and how do you know how many 'values' can fit in within the range? :-\
THANKS IN ADVANCE ;D
--- End quote ---
http://img69.imageshack.us/img69/3933/trigonometry.png
This is a good way for those that are not accustomed to radian calculation in attempting these sort of questions ...
BlackBunny103:
Guys, can you please explain to me Q1 ON 2009 Paper 2? I don't know how to get the answers as shown in the mark schemes.
Thanxx :D
J.Darren:
--- Quote from: BlackBunny103 on June 07, 2010, 04:06:27 pm ---Guys, can you please explain to me Q1 ON 2009 Paper 2? I don't know how to get the answers as shown in the mark schemes.
Thanxx :D
--- End quote ---
i ) Subsitute x = 0, the range would be greater than e^-1.
ii ) f(x) = e^(x+1)
y = e^(x+1)
ln y = (x+1) ln e
ln y = x + 1
ln x = y + 1
ln x - 1 = y
iii ) the domain of f-1(x) = the range of f(x), i.e. x > e^-1
Dibss:
Anyone who can upload or send me a link to the O/N 09 papers? I think only the mark schemes are available on FEP and Xtreme Papers...
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version