Qualification > Math
Additional Math Help HERE ONLY...!
Dibss:
--- Quote from: Dibss on June 03, 2010, 10:12:36 pm ---ok, let me go check the mark scheme and i'll get back to you!
--- End quote ---
it's from M/J 05 P2 =]
astarmathsandphysics:
My mistake - I read 165000 home which have both computer and dishwasher
jellybeans:
--- Quote from: A@di on June 03, 2010, 06:51:54 pm ---INCOMPLETE Q...post the paper link and ms..
--- End quote ---
ohh sry.
D: its incomplete?
--- Quote from: astarmathsandphysics on June 03, 2010, 07:37:39 pm ---answer to the venn diagram question
--- End quote ---
--- Quote from: Dibss on June 03, 2010, 08:45:25 pm ---Check the attachment. Hope it helps =]
--- End quote ---
THANK YOU ;D ;D ;D !!
jellybeans:
HELLLLLLLP please ;)
thank you& its NOT an incomplete question :)
Ghost Of Highbury:
oh damn..........this is such a bloody hard q......i remember givin this to ma teacher and he couldnt solve it..........
there are two different cases you need to consider......the first is that he selects 3 sweets all of different kinds......u knw that he can choose any 3 flavours frm the 6 available.....the number of selections is 6C3=20
the second case is that 2 of the sweets are the same and the other one is of a different flavour. when he chooses the first sweet, he has a choice between 6 different flavours. when he chooses the second sweet he still has a choice between 6 flavours since he can select another of that
flavour. but when he selects the third sweet he has a choice of 5 flavours since two sweets have already been taken form the sixth flavour and he
cannot take a third. the number of selections is 6*5=30
so the total is 30+20=50
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