Qualification > Math
Additional Math Help HERE ONLY...!
shan2391:
guys help Q.2 in this paper(attached)
astarmathsandphysics:
--- Quote from: shan2391 on June 04, 2009, 11:11:17 pm ---guys help Q.2 in this paper(attached)
--- End quote ---
c=3 since (0,0) nusves to (0,3) b=1 since there is no scaling in the x direction and c=2 since tanpi/4=1 but 5-3=2 so there is a scaing factor 2 in the y direction
divineobsidian:
--- Quote ---
yess =)
so the eqn will be joined together, since y is the common subject
becomes x2-5x+18=mx+2
then bring everything over
x2-5x-mx+18-2=0
x2-x(5+m)+16=0
so here the components of the quad eqn is fulfilled =)
so ax2+bx+c=0
a=1 b=(5+m) c=16
since tangent never touches the curve,
we use b2-4(a)(c) < 0
so substitute....
(5+m)2-4(1)(16)<0
25+10m+m2-64<0
m2+10m-29<0
solve quadratically, im sure u'll get ure answer :D
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k thanks arc sorry for long reply i was sleeping in asia
edit:yeah By the way vanib i did OR on the P1 but i think i kinda messed up
Sweet_03:
I have a Q on vectors
If You Have a vector AB
and You need to find th unit vector
is this the right formula ?
1 / |AB| x AB
and to find out the magnitude ..
SQUARE ROOT of a2 + b2
Is this Right ?
vanibharutham:
yes correct Sweet_03
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