Additional Math Help HERE ONLY...!

[shan2391]

guys help Q.2 in this paper(attached)

[astarmathsandphysics]

guys help Q.2 in this paper(attached)

c=3 since (0,0) nusves to (0,3) b=1 since there is no scaling in the x direction and c=2 since tanpi/4=1 but 5-3=2 so there is a scaing factor 2 in the y direction

[divineobsidian]

yess =)

so the eqn will be joined together, since y is the common subject
becomes x²-5x+18=mx+2
then bring everything over
x²-5x-mx+18-2=0
x²-x(5+m)+16=0
so here the components of the quad eqn is fulfilled =)
so ax²+bx+c=0
a=1 b=(5+m) c=16

since tangent never touches the curve,
we use b²-4(a)(c) < 0
so substitute....
(5+m)²-4(1)(16)<0
25+10m+m²-64<0
m²+10m-29<0

solve quadratically, im sure u'll get ure answer  

k thanks arc sorry for long reply i was sleeping in asia

edit:yeah By the way vanib i did OR on the P1 but i think i kinda messed up

[Sweet_03]

I have a Q on vectors

If You Have a vector AB
and You need to find th unit vector
is this the right formula ?

1 / |AB| x AB

and to find out the magnitude ..
SQUARE ROOT of a² + b²

Is this Right ?

[vanibharutham]

yes correct Sweet_03

[Sweet_03]

aha ! Finally i got it :-DD
Thnnnx aLot

and Good Luck everyone

[vanibharutham]

i have a feeling realtive velocity might shwo up im scared 

[Ghost Of Highbury]

guys help Q.2 in this paper(attached)

c=3 since (0,0) nusves to (0,3) b=1 since there is no scaling in the x direction and c=2 since tanpi/4=1 but 5-3=2 so there is a scaing factor 2 in the y direction

how do u find the value for a and b?"??
plzz explain clearly

[astarmathsandphysics]

I meant a=2

[Ghost Of Highbury]

y is b=1....didnt get "there is no scaling in the x-direction" ... any other method

[nid404]

To a cyclist travelling due south on a straight horizontal road at 7 m/s, the wind appears to be
blowing from the north-east. Given that the wind has a constant speed of 12 m/s
, find the direction
from which the wind is blowing.

Have a look aadi.....if you get the other part lemme know

[Ghost Of Highbury]

shudnt 135 come between 7 and 12?

[nid404]

shudnt 135 come between 7 and 12?

cos inverse of 7/12 =/ 135...equal to abt 55

[Ghost Of Highbury]

but 135 shud come between 7 and 12 righ?

[nid404]

but 135 shud come between 7 and 12 righ?

not possible....how r u saying that??