Qualification > Math
Additional Math Help HERE ONLY...!
ineedaz:
yeah i guess so... but speking in terms of the way the questions are set... like for example, todays first question in paper 1 was overly stright forward...maybe in paper 2 we might not get lucky... i don't know tho, just a suggestion.. i would definetly prepare harder!!
and sometimes, permutations can be a b**** if u know what i mean!! and so can matrices...pretty much everythng, depending on the way questions are set..
sweetsh:
I find these things easy, anyway good luck for us!
divineobsidian:
can someone do an example on inverse functions,binomials and real routes
sorry for requesting so much but maybe others also have problems ;)
all help for last paper was truly appreciated
vanibharutham:
Inverse Functions
Inverse functions are really simple, but you have to follow a step-byy-step method.
If you are given an f(x) = 2x + 19
And you are told to find f-1(x) you can do it by this method:
STEP 1: write out your f(x) formula, replacing the f(x) with y
Therefore, y = 2x + 19
STEP 2: Swap all your x's and y's
Therefore, x = 2y + 19
STEP 3, Make y the subject
Therefore,
2y = x - 19
y = (x-19)/2
STEP 4, Replace the y, with f-1(x)
Therefore,
f-1(x) = (x-19)/2
They might give you a harder question involving quadratics...
Lets say
f(x) = 2x2+18
y = 2x2+18
x = 2y2+18
2y2 = x - 18
y2 = (x - 18) / 2
y = + or - SQUARE ROOT of (x - 18) / 2
Be careful with the inverse in the quadratics, because you have to make sure the inverse fits within the domain or range given of the function
Ghost Of Highbury:
binomial theorm..
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the power is usually low in additional math for binomial theorm as in 1<= n <= 10
some of us who find combination method difficult use the triangle law
its the pascals triangle
its like this
1 1
1 2 1
1 3 3 1
1 4 6 4 1
and so on ...keep on adding the middle numbers of the previous row..to get the next one..
for example if they say to (a+b)^4 --> the power is 4 soo chk out d pattern in the triangle
its 1 4 6 4 1
these numbers will act as coeffecients..
therefore (a+b)4 =a4 + 4a3b + 6a2b2 + 4ab3 + b4
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u put the coefficients one by one..and keep on decreasing the power of a and increasing b's power...
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there is also a combination methon for that..
i'll explain it later
:)
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