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Computer studies help HERE only !!

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CrEaTuRe_X:

http://www.freeexampapers.com/Dndex.php?d=SUdDU0UvQ29tcHV0ZXIgU3R1ZGllcy9DSUUvMjAwNSBKdW4=&catagory=
This is the paper ( may/june 05.)
Last question

This is what I wrote, Need someone to tell me weather correct or not.Thankyou.

Set "Distinction" "Mert" "Pass" "Fail"

While mark <= 25 do
Input mark
  If mark >69 than "Distinction"
  if mark >60 AND <69 than "Mert"
  If mark >50 AND <59 than "Pass"
  End if
  Print Distinction Merit Pass Fail

 

astarmathsandchemistry:

--- Quote from: CrEaTuRe_X on May 24, 2009, 01:42:49 pm ---
http://www.freeexampapers.com/Dndex.php?d=SUdDU0UvQ29tcHV0ZXIgU3R1ZGllcy9DSUUvMjAwNSBKdW4=&catagory=
This is the paper ( may/june 05.)
Last question

This is what I wrote, Need someone to tell me weather correct or not.Thankyou.

Set "Distinction" "Mert" "Pass" "Fail"

While mark <= 25 do
Input mark
  If mark >69 than "Distinction"
  if mark >60 AND <69 than "Mert"
  If mark >50 AND <59 than "Pass"
  End if
  Print Distinction Merit Pass Fail

 







--- End quote ---
i am sorry but this is completely wrong.......correct answer.....................

Ghost Of Highbury:
i guess its this way
-------------------------------
we take sum, average --> for average...
and as the markscheme says...min and max...too,,,,to compare the values and swap them accordingly..
we limit count to 24 as there are 24 hours in a day..and they want the readings hourly
the markscheme sets the min too 100  and max to 0....because a normal temperature reading for a day (0-50) will fall atlesast in 1 range
============================
sum = 0
min = 100
max = 0
count = 1 (initially)
let the temp be x

for (count=1;count<=24;count +1)
   {
     input x
     F= (x*1.8) + 32
     sum = sum + F
     if F <min, min = F
     if F >max, max = F
(note theres no else)
increment count
                                      }

average = sum/24
print average, max, min

astarmathsandchemistry:

--- Quote from: eddie_adi619 on May 24, 2009, 01:49:11 pm ---i guess its this way
-------------------------------
we take sum, average --> for average...
and as the markscheme says...min and max...too,,,,to compare the values and swap them accordingly..
we limit count to 24 as there are 24 hours in a day..and they want the readings hourly
the markscheme sets the min too 100  and max to 0....because a normal temperature reading for a day (0-50) will fall atlesast in 1 range
============================
sum = 0
min = 100
max = 0
count = 1 (initially)
let the temp be x

for (count=1;count<=24;count +1)
   {
     input x
     F= (x*1.8) + 32
     sum = sum + F
     if F <min, min = F
     if F >max, max = F
(note theres no else)
increment count
                                      }

average = sum/24
print average, max, min



--- End quote ---
oh so you just put the counter to 24 and do the rest like usual??
thanks man really helped
+rep :D

Ghost Of Highbury:
hey creatur x ... its not completely wrong..ur logic is still correct..
only minor changes required..

========
Set m, p , d, f

While x <= 25 do (don't use mark again here, use another variable like count)
Input mark
  If mark >69 then then d=d+1
  else if mark >= 60 AND <=69 then m=m+1
  else If mark >=50 AND <=59  then p=p+1
  else f=f+1
  
print m, p, d, f

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