Physics Help HERE ONLY !!

[Shogun]

wait lemme check

[Shogun]

hmm its true u do have to use the formula
velocity= frequency*wavelength
so to find wavelenght, change postioins of formulat to (velocity/frequency)
so it would be (3*10^8)/(5*10^14)
u get 6*10^-7

just exactly mana said

but mark scheme only says 6*10
its either they want only 6*10 and if u put any (^number) u still get marks OR u reaaly have to get 6*10 or the mark scheme is worng

but im pretty sure what we did is correct..

[MaNa]

hmm its true u do have to use the formula
velocity= frequency*wavelength
so to find wavelenght, change postioins of formulat to (velocity/frequency)
so it would be (3*10^8)/(5*10^14)
u get 6*10^-7

just exactly mana said

but mark scheme only says 6*10
its either they want only 6*10 and if u put any (^number) u still get marks OR u reaaly have to get 6*10 or the mark scheme is worng

but im pretty sure what we did is correct..

ya i guess the mark shceme is incorreect bcuz if u see the metohrd is what we did too soo yaaa

[Tutu_93]

Can anyone help me in physics ?? Im not that good in it ..
I have maany doubts :S

[sweetsh]

If you have any question please post them here and we got the best tutor in the world to answer you.

[Shogun]

would tht be me or astar

lol just joking

yup just bring them ova here

[Tutu_93]

okaai .. em october november 2008 q 2 ..
 

[asus]

hmm its true u do have to use the formula
velocity= frequency*wavelength
so to find wavelenght, change postioins of formulat to (velocity/frequency)
so it would be (3*10^8)/(5*10^14)
u get 6*10^-7

just exactly mana said

but mark scheme only says 6*10
its either they want only 6*10 and if u put any (^number) u still get marks OR u reaaly have to get 6*10 or the mark scheme is worng

but im pretty sure what we did is correct..


hey..how come u got 6*10^-7..
manah & I got 6x10^21..

[Shogun]

tutu is tht first variant or second

and i got 6x10^-7

by just deviding the velocity/frequency

        (3x10^8)
       ------------  = 6x10^-7
        (5x10^14)

[Tutu_93]

oh .. srry
Its the second
Thanks

[Shogun]

alright

[asus]

tutu is tht first variant or second

and i got 6x10^-7

by just deviding the velocity/frequency

        (3x10^8)
       ------------  = 6x10^-7
        (5x10^14)

yaa..i think yours is correct...
we need to simplify the bottom one first...
silly..

[Shogun]

2a) put different value of masses on bothe sides of the pivot  but make sure tht after using the formula (fxd) (where

f=force and d=distance) the product must be same. (then only they are balanced i.e in equilibrium)

 the distance are given for each hole to the pivot. so i recomend to take the first hole(with distance 4cm) and add mass 200g at one side of the pivot. and on the other side,  add mass 100g on the second hole (with disatnce 8 cm from teh pivot)

so when using the formula "fxd " u get on one side: 200x4=800N
                                                     and                                       
                                                   on the other side: 100x8=800N
                         - see both have the same product so it is now they are balanced(in equilibrium)


ans2b) the disc does not move or rotate as u put the mass so they are balanced so no turning effect which means no moment.

c)use formula "fxd"
               200x4=800N
               100x8=800N

d)this is the force of pivot which is downwar to get tht simply add the masses u put
100+800=900g

but rmember u can choose any mass at any distance but the product with equation "fxd" must be same

thts all,hope this helped, any confusion or difficulties or help u need, im all here

[Tutu_93]

THaaaanx 
Ill contiue solving nw .. just dont go lol

[Shogun]

ur welcome ,and no prob,ill wait

dnt frgt to +rep me (man i hate sayin this ,it makes me feel im selfish, but it seems it works for others)