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holtadit:
The speed of a cyclist reduces uniformly from 2.5 m/s to 1.0 m/s in 12 s.

(a) Calculate the deceleration of the cyclist.

deceleration = ..................................

(b) Calculate the distance travelled by the cyclist in this time.

distance = ..................................

How would u do the (b) part ? The examiners report says that it should be average speed multiplied time... but how do u get the average speed ? Please show your workings !

astarmathsandphysics:
Average speed is (u+v)/2=(2.5+10)/2=6.25

saleemsamer:

--- Quote from: astarmathsandphysics on December 27, 2009, 01:40:54 pm ---Average speed is (u+v)/2=(2.5+10)/2=6.25

--- End quote ---
it is 1.0 not 10

astarmathsandphysics:
Shoot me

\skldnb c1juk

sHOOT ME AGAIN!!!!!!!!!!!!

holtadit:
Okay I really need help in Paper 3 2008 may Question 5 (c)

Why do you haave to subtract 2.1g from 16.3 grams ?

The Examiners Report says that many student didnt understand the significance of the 2.1g melted in the 2 minutes.

So what is the significance ?

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