Qualification > Sciences

Physics Help HERE ONLY !!

<< < (136/173) > >>

Ghost Of Highbury:
don't forget to chk out the notes

sweetest angel:

--- Quote from: Adi...\m/ on June 03, 2009, 07:53:38 pm ---hey sweetsh angell
it is a wierd question
but i have tried to solve it
is the answer 160 degree
i am not sure
plz chk it and do inform me..
if not
tell me the answer
i'll try n figure out
thanks :)

--- End quote ---
its 160
says so in markscheme
Thanks for da pic attached for the answer bt if u can xaplain y u took those angles =/
i drew a common strait line for the points 'n found out that they were 5 dergrees lesser so 85-5=80 and 80+80=160 can we tke it dat way or can u plz xplain how u got it
plus the question says calculate not find out so can we still use the diagram?? ???
Thanks  ;D

Ghost Of Highbury:
look at the image
let the intersection point be called X
PQX is a straight line
<RQX = 180 - <PQN - <NQR = 10 degree
same for the other side
therefore <XRQ = <RQX = 10 degree

angle sum property of triangles = add up to 180
therefore <QXR (the question) = 180 - 10 -10 =160
hope it helped
 :)

Eamyzz:

--- Quote from: Adi...\m/ on June 03, 2009, 08:35:17 pm ---look at the image
let the intersection point be called X
PQX is a straight line
<RQX = 180 - <PQN - <NQR = 10 degree
same for the other side
therefore <XRQ = <RQX = 10 degree

angle sum property of triangles = add up to 180
therefore <QXR (the question) = 180 - 10 -10 =160
hope it helped
 :)





--- End quote ---
\


ya it definitely did u r a saint :)

sweetest angel:
omg i ACTUALLY GOT IT
amazin' gentlemen we got an einstein rit here :P
Thanks Thanks 'n gud luk tom  ;D

Navigation

[0] Message Index

[#] Next page

[*] Previous page