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Physics Help HERE ONLY !!

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Ibiza279:

--- Quote from: 247sports on June 03, 2009, 12:06:12 pm ---
--- Quote from: Ibiza279 on June 03, 2009, 11:41:03 am ---
--- Quote from: 247sports on June 03, 2009, 11:32:38 am ---I hav some quests in ppr may june 2002
 2c)
8c)
and in may june 2007
2a) and 9a)
and i need explanation i hav the markin scheme but i need to understnad it
thnk u  ;)

--- End quote ---


2c: the change in speed is 9.5 m/s cause frm 9.5,when the ball touches the grnd it comes to 0 so its 9.5 i hope thats what the mark scheme says

8c: the function of a diode is that its a rectified, it changes frm A.C to D.C so as the A.C current flows in forward bias of the diode, the diode allows the flow but when A.C flows in the opposite direction, the diode doesn't allow that so A.C changes to D.C

n for 2007 i don't hav the paper so if u give me the question, ill clear it

all the best

--- End quote ---
Thanks but sry to burst ur bubble but the answer in the markin scheme is 1.5 n 17.5 m/s  :-\
n sry i neede to ask 9c) not 8c)
n neva mind for 2007 they r all daigrams
Thanks alot aneways :)


--- End quote ---

lol sorry fer the incorrect answers well then the other alternative is first one is 9.5 - 8 and the second one is 9.5 + 8 :D
well it does make sense change in speed at that point is 1.5 n change in velocity is 17.5 sorry fer the wrong answer :)

Ibiza279:
well i gotta go now tk ppl all the best fer ur exams ! :D

Ghost Of Highbury:

--- Quote from: theigstudent on June 03, 2009, 12:18:17 pm ---could some 1 help me with
june03 paper no3___________Q3a and   @11 a and b


--- End quote ---
Q3a answer
no idea of Q10
find it attached

sweetie:
emergency case! plz help
in 1 variant paper oct 08, i couldnt do q2.d
plzzzzzzzz give me da solution
xam is morrow

theigstudent:

--- Quote from: astarmathsandphysics on June 03, 2009, 12:34:02 pm ---
--- Quote from: theigstudent on June 03, 2009, 12:18:17 pm ---could some 1 help me with
june03 paper no3___________Q3a and   @11 a and b


--- End quote ---

use a scale 100N=1cm. draw a line 12.2cm starting at the left hand pin on the bar parallel to the 1220N force, and a line 9.5 cm staring at the right hand pin parallel to th 950N force. Where these to lines meet draw a diangonal to the opposite corner of the paralllelogram. Timnes this length by 100 to get the force in N.

11a)Use aluminium or lead sheets between the source and a detector. Nothing is detected therefore an alpha emittor

b)Use the left hand rule. Deflected into paper

--- End quote ---


i didnt get the drawing part could some 1 attach the drawing
Thanks in advance
n Thanks a lot astar

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