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SGVaibhav:
solve this hard questoin


quesiton (1)(c) is hard
the answer is 24 to 28 m
how do u get that?

Shogun:
lol u got it now. see the question in a different way/manner.... u see  16.3 is not lost by the heater only... they gave u a hint tht excess heat (not from the heater ) was also applied to the ice..

what u need to do, is to take out tht excess heat (by subtracting) and u get the actuall heat supplied by the heater (which is needed for the equation)

Ibiza279:

--- Quote from: sgvaibhav on June 03, 2009, 10:54:12 am ---solve this hard questoin


quesiton (1)(c) is hard
the answer is 24 to 28 m
how do u get that?

--- End quote ---

answer is  1/2 X 12 X 5 = 30 m

but as the graph is abit curved so just take out 2-4 units, any of the whole numbers u like frm that range, frm the answer
thats what our teacher taught us n so u get the answer as 28

i hope that helps

Ibiza279:

--- Quote from: Shogun on June 03, 2009, 10:56:29 am ---lol u got it now. see the question in a different way/manner.... u see  16.3 is not lost by the heater only... they gave u a hint tht excess heat (not from the heater ) was also applied to the ice..

what u need to do, is to take out tht excess heat (by subtracting) and u get the actuall heat supplied by the heater (which is needed for the equation)

--- End quote ---

well got it now Thanks shogun that really helped :)

astarmathsandchemistry:
s that correct??

THE FOUR EQUATIONS OF MOTION CAN ONLY ONLY ONLY BE USED WHEN ACCELERATION IS CONSTANT

thanks

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