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Physics Help HERE ONLY !!
Ghost Of Highbury:
well!!..thats oct/nov 2008 paper 3 1st variant Q5.c.)
Shogun:
u are correct but see, 16.3g was melted, and from tht 2.1 melted after the heating
so 16.3 and 2.1 are not the mass melted by heater...
the one melted from heater is when 2.1 was melted from the 16.3
Ghost Of Highbury:
if 16.3 g is melted it has turned to water...
after that how can more 2.1 g melt from that melted portion
confused
plzz help shogun
astarmathsandphysics:
--- Quote from: idol2009 on June 03, 2009, 10:12:39 am ---Since no one answered my question before, i will repost it =)
Hey, I was doing the Oct/Nov 08 Paper 3, and on question 5c), it asks you to calculate the specific latent hear of fusion of ice from the results they have given you...
I usually find this pretty straightforward, but on this problem I was kind of stuck, because my answer didn't match the mark scheme...
The question goes as follows:
"Using a 40W heater, 16.3 g of ice is melted in 2.0 minutes. The heater is then switched off. In a further 2.0 minutes, 2.1 g of ice is melted.
Calculate the specific latent heat of fusion of ice from these results."
So I basically did the following calculation:
Total Energy supplied = 40 x 120 = 4800 J
Total Mass melted by heater = 16.3 g
Specific latent heat = 4800/16.3 = 294.5 J/g
I don't understand what I've done wrong, and what the switching the heater off and the further 2 mins has to do with it?
Any help would be appreciated thanks!
--- End quote ---
The answer is here.
https://studentforums.biz/index.php/topic,1798.msg27218/topicseen.html#msg27218
IGSTUDENT:
Its really nice to know that folks are involved so much in the subjects and not just exam oriented and have the time and inclination to share the knowledge.
what are u planning to pursue..astrophysics? or is it chem ,,u are a master in that too
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