Qualification > Sciences
Chemistry Help HERE ONLY !!
Priceless:
hey ya....i du as a matter of fact....pm me ur email...i ll send it across 2 u :)
MaNa:
--- Quote from: Priceless on June 11, 2009, 02:05:47 pm ---hey ya....i du as a matter of fact....pm me ur email...i ll send it across 2 u :)
--- End quote ---
thankyou so mcuh cheak ur messages
i have pmd uL)
lana:
hi ... can anyone explain to me question 16 in paper 1 m/j/07 thanks ...!!! i think it should be B but the mark scheme says it's C
Ghost Of Highbury:
S has many oxidation states including -2,0,2,4,6...
in this particular reaction the oxidation state of S is "+2"
a decrease in oxidation state - reduction
an increase in oxidation state - oxidation
1.) S + O2 -> SO2
here at the left handside, as sulphur exists itself (not compound), the oxidation state is 0
at the right hand sidde it forms a compound and gains an oxidation state of +2 = this is oxidation
whereas O has an oxidation state of "0" in the left hand side and decreases to -4 in the right hand side
this is reduction
therefore its redox
---------
2.) the sulphur gains oxygen atoms (oxidation) and the oxidation state of oxygen reduces..(reduction)
therefore it is redox
so the answer is "C"
1 and 2
lana:
thank you =]
+rep
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