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Chemistry Help HERE ONLY !!

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Ghost Of Highbury:
okk..got it so it will be (56*2)/196 *100 = 57.1 %
 :)

Priceless:

--- Quote from: aquarian93 on May 31, 2009, 04:09:42 pm ---i need help wid question 3 c the 2nd part.
chem p3 oct 2008

anyone care to help? i dont get it.


thanks

--- End quote ---

lol i wz just gonna say da same thng1!!! gud luck 2 u both ;)

nid404:

--- Quote from: aquarian93 on May 31, 2009, 04:09:42 pm ---i need help wid question 3 c the 2nd part.
chem p3 oct 2008

anyone care to help? i dont get it.


thanks

--- End quote ---

1st variant

Mass of 1 mol of the hydrated oxide=196g
Mass of iron=56x2=112g
%iron in the oxide=112/196x100=57%

2nd variant

mass of water=36g
%water in the oxide=36/196x100=18.4%

Ghost Of Highbury:
hahaha nid,,
answered both of themm

was abt to do that..
lol.. :)

aquarian93:
thanks guys!
i was toking abt 1st variant
bt guys, i dnt get how u get 57%

the mass is 196
hw do u get 112? :S

and in the same paper i dont understand 5b the third part, cn sum1 explain pls? thank you!

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