Author Topic: Maths & Physics Help  (Read 9038 times)

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #15 on: March 01, 2009, 02:44:34 pm »
Will pm you

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #16 on: March 05, 2009, 01:12:41 pm »
Another satisfied customer. My scanner saved all the scans as a 128MB file and I had still to learn to use Latex. Luckily she lives in London so I met her at a train station on my way to a student and gave her a brown envelope.
« Last Edit: March 05, 2009, 01:24:52 pm by astarmathsandphysics »

Offline roma

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Re: Maths & Physics Help
« Reply #17 on: March 18, 2009, 12:42:38 pm »
Hello, me again! I've been a set a coursework but i will be tested on it. So i have to learn the method used in each question and i will have a test on it which will require me to use the same methods on the coursework. I was hoping you could have a look at it for me, so that i know im learning the right stuff

Thankz

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #18 on: March 18, 2009, 12:55:28 pm »
Yes he it is posted here. Cant tell now am on phone

Offline roma

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Re: Maths & Physics Help
« Reply #19 on: March 27, 2009, 12:17:55 pm »
have you looked at it yet?

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #20 on: April 08, 2009, 07:12:12 am »
Dont i tell you make a nuisance of yourself? Am asleep.

Offline roma

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Re: Maths & Physics Help
« Reply #21 on: April 08, 2009, 12:40:47 pm »
Can you PLEASE help me then?

Offline roma

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Re: Maths & Physics Help
« Reply #22 on: May 06, 2009, 06:39:58 pm »
Hey, i needed some help on this question.

Prove p = 0.08512 B = 0.01881 A = 0.03119 simultaneously,
20 =1/(A + B)
23 =1/(A + Be^-5p)
25.5 =1/(A + Be^-10p)

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #23 on: May 06, 2009, 07:42:44 pm »
2 hours

Offline roma

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Re: Maths & Physics Help
« Reply #24 on: May 06, 2009, 09:13:44 pm »
Any luck?

Offline omarsubei

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Re: Maths & Physics Help
« Reply #25 on: May 06, 2009, 10:38:35 pm »
Hi my exam's in 12 hours, and I just don't get statistics. Please help with this question,

Consider the 10 data items x1, x2, ... x10. Given that Sum(xi)  = 1341 and the standard deviation is 6.9, find the value of the mean .

The answer is:

6.92 = 1341/10 - mean2

and then the answer works out to be +/- 9.3 .

I get the method, I just don't get why they divided by 10 ?

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #26 on: May 06, 2009, 10:47:21 pm »
There must be more to the question than that. Cabn you post the question?

Offline omarsubei

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Re: Maths & Physics Help
« Reply #27 on: May 06, 2009, 11:01:01 pm »
I'm sure that's the whole question. I don't know what you mean by post it

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #28 on: May 06, 2009, 11:13:23 pm »
This is an old topic . Can you you ropost to make it current?

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #29 on: May 07, 2009, 09:05:07 am »
Hey, i needed some help on this question.

Prove p = 0.08512 B = 0.01881 A = 0.03119 simultaneously,
20 =1/(A + B)
23 =1/(A + Be^-5p)
25.5 =1/(A + Be^-10p)

1)20 =1/(A + B)
2)23 =1/(A + Be^-5p)
3)25.5 =1/(A + Be^-10p)


Turn everything upside down

1/20 =(A + B)
1/23 =(A + Be^-5p)
1/25.5 =(A + Be^-10p)
top take away next onw gives B-Be^-5p=3/460 (4) and top take the third gives 5.5/510=B-Be^-10p Divide these 2 equtions by each other to give

(1-e^-5p)/(1-e^-10p)=0.604

sub x=e^-5p to give(1-x)/(1-x2)=0.604

so 1-x=0.604-0.604x2
so0.604x2-0.604x+0.396=0 Solve this and sub into 4 to find B then into 1 to find A