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astarmathsandphysics:

xf(x)= 2x(x+2)/5=2x^2/5+4x/5 integrate to get 2x^3/15+2x^2/5
then put limits in to get (2/15+2/5).0=8/15

nid404:
but it's 2(x+2)/5 nd not 2x(x+2)/5

astarmathsandphysics:
It says x.f(x)

nid404:

--- Quote from: astarmathsandphysics on December 20, 2009, 07:38:49 pm ---It says x.f(x)

--- End quote ---
sorry my bad

Tumble Bug:

--- Quote from: astarmathsandphysics on December 20, 2009, 05:16:00 pm ---xf(x)= 2x(x+2)/5=2x^2/5+4x/5 integrate to get 2x^3/15+2x^2/5
then put limits in to get (2/15+2/5).0=8/15

--- End quote ---

omg thank you so much dude!!!
:)  :D

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